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简单用ScrollContainer实现滚动效果，真正要好话，估计得自己用draw_string绘制，偷个懒。
extends Node2D
## 开奖号码
@export var lotterNum :String = "917651"
## 滚动速度
@export var scrollSpeed :int = 10
@onready var number: Control = $Label
@onready var scroll_label: Label = $ScrollContainer/Label
@onready var lottery_label: Label = $Label
@onready var scroll_container: ScrollContainer = $ScrollContainer
var oldScreenValue :int = -100 # 保存原有滚动值，当没变化时，表示到底
var currentNumber :int = 0 # 当前显示第n个值
func _ready() -> void:
setScollLabelValue() # 设置滚动值
var timer = Timer.new()
timer.wait_time = 0.01
timer.autostart = true
timer.timeout.connect(func():
scroll_container.scroll_vertical += scrollSpeed
# 滚动到底的处理
if scroll_container.scroll_vertical==oldScreenValue:
number.get_children()[currentNumber].text = lotterNum.substr(currentNumber,1)
number.get_children()[currentNumber].visible = true
currentNumber+=1
if currentNumber==6:
timer.stop()
scroll_container.visible = false
return
scroll_container.scroll_vertical=0
setScollLabelValue()
else:
oldScreenValue=scroll_container.scroll_vertical
)
add_child(timer)
func setScollLabelValue() -> void:
number.get_children()[currentNumber].visible = false # 原标签隐藏
scroll_container.position.x = number.get_children()[currentNumber].position.x + 150 # 滚动内容定位
scroll_label.text = ""
for i in range(20):
scroll_label.text += "\n" + str(i % 10)
for i in range(int(lotterNum.substr(currentNumber,1))):
scroll_label.text += "\n" + str(i % 10)